The background for this algorithm is as follows:
Step 3, below, uses CALGO 199 (this link is to a PDF file which requires the Adobe Acrobat Reader) from "Collected Algorithms from CACM".
1. Determine if year is 2- or 4-digits and correct if necessary. Ideally, the Year will be 4-digit, otherwise possible year range will be restricted to 1920 to 2019 using the 'cutoff' value shown.
cutoff = 20 ' Arbitary pivot year (1920)
if year < 100 then ' year only consists of last 2-digits
if year < cutoff then
year = 2000 + year
else ' year >= cutoff
year = 1900 + year
end if
end if
2. Determine if year is a leap year or not, after converting to 4-digits.
Leap Year = False ' Assume not a Leap Year to start
Factor = 0 ' Factor is amount to add to Day Index to
' give Calendar Number assuming leap year
' result remains 'False'
if right (year, 2) = 0 then
' If century year and divisible by 400
if (left (year, 2) mod 4) = 0 then
Leap Year = True
Factor = 7
end if
else
' If not a century year and divisible by 4
if (right (year, 2) mod 4) = 0 then
Leap Year = True
Factor = 7
end if
end if
3. Determine the Day of the Week using one of the following methods:
a. Calculate Julian Day Number using CALGO 199 (JDAY)
setting Year = Input Year; Month = 01; and, Day = 01
as we want the day on which the first day of the year occurs
Calculate Remainder Plus 1 using formula: (Julian MOD 7) + 1
Determine Day of Week for result and adjust such that
Sun = 1, Mon = 2, ..., Sat = 7
We want the numeric value only for later and Sunday must equal day #1
b. Use ANSI COBOL 89 Instrinsic Function (see examples below) to obtain
the Julian day number instead of CALGO 199 (JDAY) and then proceed as
for method 'a' above
MOVE FUNCTION INTEGER-OF-DATE (yyyy0101) TO receiving-field
MOVE FUNCTION INTEGER-OF-DAY (yyyy001) TO receiving-field
Base date for ANSI Intrinsic Date Functions is 01-JAN-1601 which was a Monday
which means that 1601 used calendar #2.
4. Determine the Calendar Number from the obtained data as follows:
if Leap Year = False then
Calendar Number = (Corrected) Day-Of-Week Number
else
Calendar Number = (Corrected) Day-Of-Week Number + Factor
end if
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